Intersection Sph - Pla

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  • Intersection Sph - Pla

    Hi .

    How can I build a circle between a sphere and a plane?

    Thank you

  • #2
    As long as the sphere and plane physically intersect each other you can use either INTCIR (intersect circle) or INTELP (intersect ellipse) - see code below.


    Code:
    INTCIR          (NAM=CIRCLE, CSY=CMMA$CSY, EL1=SPH(1), EL2=PLA(1), MOD=NOE)
    
    INTELP          (NAM=ELLIPSE, CSY=CMMA$CSY, EL1=SPH(1), EL2=PLA(1), MOD=NOE)
    Neil Challinor
    PC-DMIS Product Owner

    T: +44 870 446 2667 (Hexagon UK office)
    E: [email protected]

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    • #3
      I don't know about Quindos, but you can check/ create the result with a little trig :
      The distance between the center of the sphere and the plane divided by the sphere radius helps calculating the angle (Angle=ASIN(dist/radius))
      The radius of the circle is given by CIRC_RAD=sphere radius* cos(angle).
      The center of the circle is given by sphere center (xyz) + distance * plane vector.

      On PC-DMIS, it would be :
      ASSIGN/V1=DOT(SPH1.XYZ-PL1.XYZ,PL1.IJK)
      ASSIGN/V2=ASIN(V1/SPH1.R)
      ASSIGN/V3=SPH1.R*COS(V2)
      ASSIGN/V4=SPH1.XYZ+V1*PL1.IJK

      Then create a generic circle with V4.XYZ as center, V3 as radius and PL1.IJK as vector.

      Intersecting the sphere and the plane gives directly the result

      Comment


      • #4
        JEFMAN , unfortunately, your method is not correct - with that you will get the mirrored circle. Note that F1 is created above the sphere center while the plane is actually below. The distance from the center is OK, but not the direction of the distance.

        V1 should really be DOT(PL1.XYZ - SPH1.XYZ, PL1.IJK), right?


        jefman_cir_sph_pln.PNG
        AndersI
        SW support - Hexagon Metrology Nordic AB

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        • JEFMAN
          JEFMAN commented
          Editing a comment
          Right ! (I'm not at the cmm...)

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