perpendicularly on a chamfer/angled plane

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  • perpendicularly on a chamfer/angled plane

    Hello all
    I found this weird callout which i really cant grab my head around.
    Its callout of perpendicularly on a angled (almost like a chamfer),
    The references:

    A = a straight plane 0,0,1 IJK
    B = a straight plane perpendicular to A 1.0.0 IJK

    And the element which the callout is for is a very short plane (2.5mm x 25 degrees). 0, -0.906, 0,422 IJK
    How can that chamfer / angled plane be perpendicular to A and B?
    Should i measure it as a line or plane?
    Is it the engineers fault, and maybe he ment angularity? or am i getting it wrong

  • #2
    which datum is this perpendicularity called out to ? most likely meant angularity ,

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    • #3
      yeah that's silly. Maybe he was trying to invent a new way to call out perpendicularity? I presume the 25° angle is basic?
      Even then, still not per asme y14.5m. i'm with gibsonridge , probably meant angularity.

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      • #4
        Originally posted by louisd View Post
        yeah that's silly. Maybe he was trying to invent a new way to call out perpendicularity? I presume the 25° angle is basic?
        Even then, still not per asme y14.5m. i'm with gibsonridge , probably meant angularity.
        Yeah i would assume so. But on the drawing 25 angle is dimensioned as a "normal dimension"., not basic/ted
        Also im living the ISO world

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        • #5
          I think your imagineer wants to use "angularity" and doesn't know how =(
          Beep beep beep..

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          • louisd
            louisd commented
            Editing a comment
            Or take a shoe off.

          • KIRBSTER269
            KIRBSTER269 commented
            Editing a comment
            maybe in ISO there is a new callout, crookedlarity?

          • DAN_M
            DAN_M commented
            Editing a comment
            What in the Steve Irwin is crocodocularity?!

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