I don’t use iterative aligns much. I understand that they repeat until the set target radius is achieved. And the origin defaults to the cad origin right? So I have a part with datum targets A1, A2, A3 are at different heights (B1,B2, are inline). So if the cad origin is at the A1 point my zero would be there? Also, Would you stay in the iterative align to check the rest of the points and also dimension from that alignment? Or do you have to translate to A1,B1,C1 after the 3-2-1 iterative align. I ask for 2 reasons 1) because What happened the last iterative I did I had to use a different alignment after The 3-2-1 iterative and when I recalled the iterative it went back and measured the targets again. So my thoughts are if you translate origin after then you won’t be recalling a iterative anymore. So that brings me to 2) if I did translate to A1 after the iterative and tried to check the location of A2 & A3 points the location SHOULD be the exact nominal? ...... last thought is after the iterative I could go back and probe the target points and construct an offset plane from A1,A2,A3 and do a regular 3-2-1 alignment. But that just seems pointless if you are already “locked in” from the iterative.
Iterative alignment origins
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If i follow you, you're saying recalling an iterative make it go and remeasure the points (i.e. execute the command again) - I don't know if I've tried that but it sort of (in a pc-dmis kind of way) makes sense.
Best option would be to save alignment straight after the iterative and recall that (you could even insert an empty alignment to save it internally instead of externally).
Applications Engineer
Hexagon UK
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Originally posted by NinjaBadger View PostIf i follow you, you're saying recalling an iterative make it go and remeasure the points (i.e. execute the command again) - I don't know if I've tried that but it sort of (in a pc-dmis kind of way) makes sense.
Best option would be to save alignment straight after the iterative and recall that (you could even insert an empty alignment to save it internally instead of externally).
alignment/end... Could I also have translated origin on A1 for -z- (A1 is the highest point of the 3 A datum target which all the dimension come from), B1 for -y-, and c1 for -x- because all 3 of the A points = 0 same for B and C points?
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