Looking for some help with the 1.839/1.849 distance. This callout is not a Cartesian distance . Its asking for the circumference value from point to point. I'm thinking this is going to need some combination of variables. Using 2015.1 CAD. Thanks!
Distance with circumference
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Originally posted by kingsld1 View PostJust to be difficult.....
What if the diameter is significantly out of round?
ASSIGN/V1=SCN1.HIT[1..(SCN1.NUMHITS1)].XYZ
ASSIGN/V2=SCN1.HIT[2..SCN1.NUMHITS].XYZ
ASSIGN/V3=SUM(SQRT(DOT(V2V1,V2V1)))
ASSIGN/V4=SQRT(DOT(SCN1.HIT[SCN1.NUMHITS].XYZSCN1.HIT[1].XYZ,SCN1.HIT[SCN1.NUMHITS].XYZSCN1.HIT[1].XYZ))
ASSIGN/LENGTH=V3+V4
The uncertainty on this method should be approximately half of the density of the scan.
For an open scan, keep only V3...
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There is the feature type CURVE available under constructions, which has a length that can be dimensioned. With measuring points close enough it might give a good approximation.AndersI
SW support  Hexagon Metrology Nordic AB
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You can download the core manual, chap.26... Print it, read it, and try to find some memories of maths or trig...
Assignments is only a tool box, but a very nice tool box !
ftp://ftp.wilcoxassoc.com/docs/v2016.0manual/ (I'm unable to add the link with "add link" button... )
But it seems to work "alone" !
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Does anyone know how to write a formula to the distance between 2 points and divide by2.
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