Polar Dimensioning

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  • Polar Dimensioning

    I have some holes that are called out with polar angle and polar radius. The problem I'm having, and I don't remember having this come up before, is the hole that is at 0 degrees or 360 degrees depending on how you look at it will show out of print if I put in 0 degree nominal with a tolerance of +/-.5 degrees because it is reporting 359.9446 degrees which is in print.

    EX:

    Measured Nominal +Tol -Tol Dev OutTol
    359.9446 0.0000 .500 .500 359.9446 359.4496

    I'm know it something simple in a setting somewhere, but it's been one of those days.

    Thanks
    Dan

  • #2
    Yeah, there is a setting for polar degrees to be reported as +/-180 degrees, but I am not sure where it is. I have read about it on the site before. I would guess in the F5 setup, in the list.
    sigpic
    Originally posted by AndersI
    I've got one from September 2006 (bug ticket) which has finally been fixed in 2013.

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    • #3
      Originally posted by Matthew D. Hoedeman
      Yeah, there is a setting for polar degrees to be reported as +/-180 degrees, but I am not sure where it is. I have read about it on the site before. I would guess in the F5 setup, in the list.

      that was it... can't believe I just looked in that area and totally missed that box... geez

      Thanks!

      Comment


      • #4
        It's a pain in the neck, think I've requested B&S for a fix, but it's probably been ignored. My problem is, I've got a single program that sometimes looks for holes at polar angles of 0° and other times, 180° so I can't win.

        Let me tell ya, having an angle off by 359.984° from nominal with a tolerance of .5°, REALLY throws off your Cpk.

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        • #5
          Have you tried using the tolerance values to make it OK?

          I know you can use a negative value (type in -1.0) for the positive tolerance for a point and 0.5 for the negative tolerance and get a range of -1.0 to -0.5 as the GOOD band. Have you tried typing in a negative 359.5 for the negative tolerance value? The double negative (Pcdmis assumes - for the value in the negative tolerance 'cell') will make it a positive tolerance.
          sigpic
          Originally posted by AndersI
          I've got one from September 2006 (bug ticket) which has finally been fixed in 2013.

          Comment


          • #6
            I've tried the -359.5 but my out of tolerance value is .4446,

            I'll stick with the +/- 180 degree thing for this program. This would be a nice feature if you could change it from +/-180 degrees back to 0/360 degrees in different parts of the program and not just a change to the whole program. I have some programs that I would like to have both of these option in the same program depending on how the drawing calls them out.

            I used to like it when my avail software knew the 0 degrees +/-.5 knew that 359.5 to .5 was in tolerance.

            I've used this feature before in my programs and not sure why today I had a log jam in my head could not find it. You know how that goes.

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            • #7
              ok..... that did not work, did not notice it yesterday but it does the same thing when it goes past 180 degrees.

              Ex: negative 180 hole measured positive 179.975 and showed it way out.

              hmmmm....... gots to be away around this.

              Maybe its just a ver3.6 thing.

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              • #8
                Doesn't that stink that when something isn't working the way we think it should we don't know whether it is something that we are doing wrong or missing or if it is a software bug and maybe it's fixed in the next version or MR?
                sigpic

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                • #9
                  Yes it does.... I really hated it when I first learned this software and people would walk into the lab and I'm sitting there like a lost puppy trying to find out what I was doing wrong!

                  Comment


                  • #10
                    Oh, you mean yesterday?
                    sigpic
                    Originally posted by AndersI
                    I've got one from September 2006 (bug ticket) which has finally been fixed in 2013.

                    Comment


                    • #11
                      in the true postion dialog box make sure you check "from start point of axis" then your first hole should be 0.000 deg

                      Comment


                      • #12
                        Originally posted by Matthew D. Hoedeman
                        Oh, you mean yesterday?
                        Yes it was yesterday....but I think I looked like a mean ole dog instead of lost puppy
                        Last edited by DrBudman; 06-01-2006, 11:59 AM.

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                        • #13
                          Originally posted by RUSTY COG
                          in the true postion dialog box make sure you check "from start point of axis" then your first hole should be 0.000 deg

                          not using true position

                          Comment


                          • #14
                            I was chomping at the bit to help on this one. I have a "semi" solution to your polar reporting problem. It is not going to report the angle location as negative but it will stop the out of tolerance reporting that you have been getting on in tolerance features. When the hole is located on the negative angle side (in the case of the example -Y) we convert it's mislocation to a positive angle then throw up a comment informing the operator that the angle is actually negative. How you word the comment depends on the IQ of your monkeys. You may need a lot a verbiage explaining what is going on. This solution will allow accurate reporting except only negative deviation will be positive in the dimension block, hence the comment. This is not my idea of a true solution but the best I could think of. Hopefully there is a better solution out there.
                            Code:
                            CIR1       =FEAT/CIRCLE,RECT,OUT,LEAST_SQR
                                        THEO/2,0,0,0,0,1,0.25
                                        ACTL/1.9512,-0.0835,-0.0001,0,0,1,0.2168
                                        MEAS/CIRCLE,4,WORKPLANE
                                        HIT/BASIC,2.125,0,0,1,0,0,2.0896,-0.0288,-0.0001
                                        MOVE/CIRCULAR
                                        HIT/BASIC,2,0.125,0,0,1,0,1.9733,-0.0214,-0.0001
                                        MOVE/CIRCULAR
                                        HIT/BASIC,1.875,0,0,-1,0,0,1.8342,-0.031,-0.0001
                                        MOVE/CIRCULAR
                                        HIT/BASIC,2,-0.125,0,0,-1,0,1.9775,-0.1702,-0.0001
                                        ENDMEAS/
                                        IF/CIR1.Y < 0
                                        COMMENT/REPT,"******************************************************"
                                                    ,"THE FOLOWING POLAR ANGLE LOCATION IS ACTUALLY NEGATIVE"
                                                    ,"******************************************************"
                                        END_IF/
                                        ASSIGN/V1 = ABS(CIR1.Y)
                            CIR1_CONST =GENERIC/CIRCLE,DEPENDENT,RECT,OUT,$
                                        NOM/XYZ,2,0,0,$
                                        MEAS/XYZ,CIR1.X,V1,CIR1.Z,$
                                        NOM/IJK,0,0,1,$
                                        MEAS/IJK,0,0,1,$
                                        DIAMETER/0.25,CIR1.D
                            DIM LOC2= LOCATION OF CIRCLE CIR1_CONST  UNITS=IN ,$
                            GRAPH=OFF  TEXT=OFF  MULT=1.00  OUTPUT=BOTH
                            AX    MEAS   NOMINAL    +TOL     -TOL      DEV    OUTTOL 
                            PR   1.9530   2.0000   0.1000   0.1000  -0.0470   0.0000 --#------
                            PA   2.4504   0.0000   0.5000   0.5000   2.4504   1.9504 -------->
                            D    0.2168   0.2500   0.0100   0.0100  -0.0332   0.0232 <--------
                            END OF DIMENSION LOC2
                            This example is in the X,Y workplane but can be applied anyway you want. The comment will only show when there is negative angle deviation. It is a shame that Wilcox can not stop positive reporting on angles. This frustrates me too. It is especially frustrating when you see in the feature block (toggled to polar) that the angle is -2.5º but in the dimension block it is 357.5º. It makes it even harder to dream up a work-around.

                            Craig
                            <internet bumper sticker goes here>

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